sebanyak 1 ml larutan NaOH 1 M ditambah air sehingga volume menjadi 1 L.Ph larutan adalah..

V₁ = 1 ml
[NaOH] = 1 M
V₂ = 1000 ml
pH= .....?
M₂V₂ = M₁V₁
M₂.1000 = 1.1
M₂ = 10⁻³ M --------> OH⁺ = 10⁻³
pOH = - log 10⁻³
= 3
pH = 14 - 3 = 11

Source https://sebuahcatatan.live/as/catatanbrain/tugas/2128046